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#2 |
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...So I dub thee Unforgiven.
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which formula? there is endless formulas. here is one...
(tau)=I(alpha) where: tau=torque I=moment of inertia alpha=angular acceleration but i dont think thats what you are looking for. ![]()
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#4 |
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DONT HATE ME CUZ YOU AINT ME!!!!
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Horsepower = How hard you hit the wall
Torque = How far the wall moves when you hit it. ![]()
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04 Oxford White MACH1,5 SPD with IUP,K&NAircharger Borla Stingers,SLP Catted X pipe,Tri-ax,SCT Flashtune,Max Mtr Spt 4 bolt adj C/C plates, Drilled/Slotted rotors all 4 corners 281 rwhp on Mustang Dyno,306 rwhp on a Dynojet 94 Black Lightning Daily Driver&85GT FACH1 Project under construction
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#6 |
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Swimming in a sea of anxiety...
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Go do your homework Tim!!!!!!
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2003 Redfire Roush Stage II #6395 377.5hp/ 372.9tq@ 8psi Small vid of blower ![]() <----Click for mods....
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#7 | |
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Giving up
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Quote:
but i know that in the formula that involves the gears of the tranny after the whole formula its divided by the gears in your tranny so would my four speed auto have more h.p than a 5spd? |
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#8 |
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...So I dub thee Unforgiven.
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i bet by tranny gears, they mean your final gear ratio, NOT the number of gears your tranny has. final gear ratio for a stock v6 99+ is 3.27 i beleive.
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#9 |
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Killing is my Business...And Business is Good!
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I know what your looking for. It has to do with torque multiplication or deduction thru drivetrain loss. It's pretty complicated and i'm sure it's out on the net somewhere, just have to go and find it.
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![]() 1988 Mustang LX |
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#10 | |
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Killing is my Business...And Business is Good!
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Quote:
Five speeds usually have more HP because they have less rotational mass.
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![]() 1988 Mustang LX |
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#12 | |
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Killing is my Business...And Business is Good!
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Torque is lost in an automatic because of more friction being created and fluid being pumped around.
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![]() 1988 Mustang LX |
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#13 | |
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technology > displacement
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Quote:
a torque converter multiplies torque...so an auto will make more torque on the low end...where the torque falls off depends on the size of the stall btw... hp = torque x rpm/5252
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My Garage |
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#14 | |
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Killing is my Business...And Business is Good!
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Your right Brian, but it is lost thru the rest of the transmission and drivetrain, especially on stock trannys. Here is some stuff to read Tim. http://auto.howstuffworks.com/automa...ansmission.htm http://auto.howstuffworks.com/transmission.htm
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![]() 1988 Mustang LX |
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#15 | |
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Registered User
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Each auto has its unique drivetrain loss. aod, c4 c6 turbo350, turbo 400, 700r4, 4l60e. Each one has different rotational mass that creates a different "transmission" of power to the wheels. This is the same for a Bigger rear end such as a ford 9 inch. It will show a lower dyno reading because of the extra rotational mass. A lighter aluminum driveshaft is an improvement based on this effect, and the fact that it is more balanced than stock. Liter rear wheels will have the same effect 18 inch saleens = bad, 15 inch bogarts = good
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"The LT2" N/A 95 z28 heads/cam/intake/11:1 355c.i. Last edited by Cammed95Z28; 04-20-2004 at 05:25 AM. |
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#18 | |
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Registered User
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12- 1000+55/the age of the car*by the time of day it is. LOL
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Lick it! Slam it! Suck it! |
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#19 |
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Ooh-Rah Marine Corps
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Tim you are thinking of torque multiplication. This is not changing the torque in your car. It is the same principle as on a 10 speed bike. In low gear you don't have to put to much effort into it because you have a mechanical advantage from the gears, the downside is that you have to pedal really fast to go anywhere. The same thing applies to cars. Numerically higher gears will multiply torque more, but your engine will have to turn more rpm to go the same speed. You need to remember that this multiplication will not show up on the dyno. If it did you would get some ungodly high torque numbers and they would be different for each gear.
If your confused by that I can try explaining it in person the next time I am at the forum.
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![]() 88 vert Be polite and professional, but have a plan to kill everyone you meet. |
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